The difference of height of two points whose parallax difference is 0.8 mm on a pair of stereo pair taken from a height ‘H’ is 100 m. If mean photo base is 95.2 mm, the flying height is

P=0.8mm=0.0008m
B=95,2mm=0.0952m
h=100m
The Equiation - P/h=B/H-h
H-h=B*h/P
H-100=0.0952*100/0.0008
H-100=11900
H=11900+100
H=12000m
Option C

d= rh/H
100X95.2/0.8 =11,900
=12,000

h=dp/(B/H)
here,
h=100 m
dp= 0.8 mm
B = 95.2 mm
H=?
using formula,
H=(95.2*10^-3*100/0.8*10^-3)
= 11,900

d=(rh/H)
r= 95.5
h=100
d=0.8
Ans=(100×95.5)/0.8=11937=12000

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