The dimensions of an open box are 52 cm × 40 cm × 29 cm. It thickness is 2 cm. If 1 cu.cm of metal used in the box weight 0.5 gm, then the weight of the box is :
A. 6.832 kg
B. 7.576 kg
C. 7.76 kg
D. 8.56 kg
Answer: Option A
Solution(By Examveda Team)
Since the box is an open one, we have :Internal length = (52 - 4) cm = 48 cm
Internal breadth = (40 - 4) cm = 36 cm
Internal depth = (29 - 2) cm = 27 cm
Volume of the metal used in the box :
= External volume - Internal volume
= [(52 × 40 × 29) - (48 × 36 × 27)] cm3
= (60320 - 46656) cm3
= 13664 cm3
∴ Weight of the box :
$$\eqalign{ & = \left( {\frac{{13664 \times 0.5}}{{1000}}} \right){\text{kg}} \cr & = 6.832\,{\text{kg}} \cr} $$
Related Questions on Volume and Surface Area
A. 12$$\pi$$ cm3
B. 15$$\pi$$ cm3
C. 16$$\pi$$ cm3
D. 20$$\pi$$ cm3
In a shower, 5 cm of rain falls. The volume of water that falls on 1.5 hectares of ground is:
A. 75 cu. m
B. 750 cu. m
C. 7500 cu. m
D. 75000 cu. m
A. 84 meters
B. 90 meters
C. 168 meters
D. 336 meters
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