Dimensional formula of Universal Gravitational constant G is-
A. M-1L3T-2
B. M-1L2T-2
C. M-2L3T-2
D. M-2L2T-2
Answer: Option D
Solution (By Examveda Team)
The dimensional formula of the Universal Gravitational constant G is derived from Newton's law of universal gravitation which states that the force of attraction between two point masses is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. Mathematically, it can be expressed as:F=G⋅m1⋅m2/r2
Where:
F is the force of attraction
G is the Universal Gravitational constant
m1 and m2 are the masses of the objects
r is the distance between the objects
To determine the dimensional formula of G, we can rearrange the formula as:
G=F⋅r2/m1⋅m2
Now, let's analyze the dimensions:
Force (F) has the dimensional formula: M1L1T-2
Distance (r) has the dimensional formula: L1
Mass (m1 and m2) has the dimensional formula: M1
Substituting these dimensions into the rearranged formula, we get:
G=(M1L1T-2)⋅(L1)2/M1⋅M1
G=M-2L2T-2
Therefore, the correct dimensional formula of Universal Gravitational constant G is M-2L2T-2.
This Question Belongs to Civil Engineering >> Applied Mechanics And Graphic Statics
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Comments (3)
In case of S.H.M. the period of oscillation (T), is given by
A. $${\text{T}} = \frac{{2\omega }}{{{\pi ^2}}}$$
B. $${\text{T}} = \frac{{2\pi }}{\omega }$$
C. $${\text{T}} = \frac{2}{\omega }$$
D. $${\text{T}} = \frac{\pi }{{2\omega }}$$
The angular speed of a car taking a circular turn of radius 100 m at 36 km/hr will be
A. 0.1 rad/sec
B. 1 rad/sec
C. 10 rad/sec
D. 100 rad/sec
A body is said to move with Simple Harmonic Motion if its acceleration, is
A. Always directed away from the centre, the point of reference
B. Proportional to the square of the distance from the point of reference
C. Proportional to the distance from the point of reference and directed towards it
D. Inversely proportion to the distance from the point of reference
The resultant of two forces P and Q acting at an angle $$\theta $$, is
A. $${{\text{P}}^2} + {{\text{Q}}^2} + 2{\text{P}}\sin \theta $$
B. $${{\text{P}}^2} + {{\text{Q}}^2} + 2{\text{PQ}}\cos \theta $$
C. $${{\text{P}}^2} + {{\text{Q}}^2} + 2{\text{PQ}}\tan \theta $$
D. $$\sqrt {{{\text{P}}^2} + {{\text{Q}}^2} + 2{\text{PQ}}\cos \theta } $$
E. $$\sqrt {{{\text{P}}^2} + {{\text{Q}}^2} + 2{\text{PQ}}\sin \theta } $$
One M in numerator and two M in denominator so the result will be M-1
(A) is absolutely the correct answer because in the given explanation of mcq ,the squared or the exponentials are missed.
G= m/s^2
M° L' T^-2