The distance between place A and B is 999 km. An express train leaves place A at 6 am and runs at a speed of 55.5 km/hr. The train stops on the way for 1 hour 20 minutes. It reaches B at :

Solution (By Examveda Team)

Time will be taken by train if it does not stop :
$$\eqalign{ & = \frac{{{\text{Distance }}}}{{{\text{Speed}}}} \cr & = \frac{{999{\text{ kms}}}}{{55.5{\text{ km/hr}}}} \cr} $$
Without stop = 18 hr
But if stops on the way for 1 hour 20 minutes before reaching B.
Total time :
= 18 hr + 1 hr 20 min
= 19 hour 20 minutes
Reaching time at B :
= 6 am + 19 hr 20 min
= 1.20 am