The distance between place A and B is 999 km. An express train leaves place A at 6 am and runs at a speed of 55.5 km/hr. The train stops on the way for 1 hour 20 minutes. It reaches B at :
A. 1.20 am
B. 12 pm
C. 6 am
D. 11 pm
Answer: Option A
Solution(By Examveda Team)
Time will be taken by train if it does not stop :$$\eqalign{ & = \frac{{{\text{Distance }}}}{{{\text{Speed}}}} \cr & = \frac{{999{\text{ kms}}}}{{55.5{\text{ km/hr}}}} \cr} $$
Without stop = 18 hr
But if stops on the way for 1 hour 20 minutes before reaching B.
Total time :
= 18 hr + 1 hr 20 min
= 19 hour 20 minutes
Reaching time at B :
= 6 am + 19 hr 20 min
= 1.20 am
Related Questions on Speed Time and Distance
A. 48 min.
B. 60 min.
C. 42 min.
D. 62 min.
E. 66 min.
A. 262.4 km
B. 260 km
C. 283.33 km
D. 275 km
E. None of these
A. 4 hours
B. 4 hours 30 min.
C. 4 hours 45 min.
D. 5 hours
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