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The equivalent length of a column of length L, having both the ends hinged, is

A. 2L

B. L

C. $$\frac{{\text{L}}}{2}$$

D. $$\frac{{\text{L}}}{{\sqrt 2 }}$$

Answer: Option B

Solution(By Examveda Team)

Both ends hinged $$l = {\text{L}}$$
Both ends fixed $$l = \frac{{\text{L}}}{2}$$
One end hinged and other end fixed $$l = \frac{{\text{L}}}{{\sqrt 2 }}$$
One end hinged another end free $$l = 2{\text{L}}$$

This Question Belongs to Civil Engineering >> Theory Of Structures

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Comments ( 3 )

  1. Amit Kumar
    Amit Kumar :
    3 years ago

    Option b and d are same correct this

  2. Ghalib 555j55j5
    Ghalib 555j55j5 :
    3 years ago

    Correct answer is option B.please correct it

  3. Atif Muneer
    Atif Muneer :
    4 years ago

    When both ends will be fixed it would be L/2

Related Questions on Theory of Structures

Y are the bending moment, moment of inertia, radius of curvature, modulus of If M, I, R, E, F and elasticity stress and the depth of the neutral axis at section, then

A. $$\frac{{\text{M}}}{{\text{I}}} = \frac{{\text{R}}}{{\text{E}}} = \frac{{\text{F}}}{{\text{Y}}}$$

B. $$\frac{{\text{I}}}{{\text{M}}} = \frac{{\text{R}}}{{\text{E}}} = \frac{{\text{F}}}{{\text{Y}}}$$

C. $$\frac{{\text{M}}}{{\text{I}}} = \frac{{\text{E}}}{{\text{R}}} = \frac{{\text{F}}}{{\text{Y}}}$$

D. $$\frac{{\text{M}}}{{\text{I}}} = \frac{{\text{E}}}{{\text{R}}} = \frac{{\text{Y}}}{{\text{F}}}$$