The graph of the equations 5x - 2y + 1 = 0 and 4y - 3x + 5 = 0, intersect at the point P(α, β). What is the value of (2α - 3β)?
A. 4
B. -4
C. 6
D. -3
Answer: Option A
Solution (By Examveda Team)
$$\eqalign{ & 5x - 2y = - 1\,.\,.\,.\,.\,.\,.\,.\,\left( {\text{i}} \right) \times 2 \cr & 4y - 3x = - 5\,.\,.\,.\,.\,.\,.\,.\,\left( {{\text{ii}}} \right) \cr & 10x - 4y = - 2 \cr & \underline {\, - 3x + 4y = - 5\,} \cr & 7x = - 7 \cr & x = - 1,\,\,y = - 2 \cr & 2\alpha - 3\beta \cr & = 2\left( { - 1} \right) - 3\left( { - 2} \right) \cr & = - 2 + 6 \cr & = 4 \cr} $$Related Questions on Coordinate Geometry
In what ratio does the point T(x, 0) divide the segment joining the points S(-4, -1) and U(1, 4)?
A. 1 : 4
B. 4 : 1
C. 1 : 2
D. 2 : 1
A. 2x - y = 1
B. 3x + 2y = 3
C. 2x + y = 2
D. 3x + 5y = 1
If a linear equation is of the form x = k where k is a constant, then graph of the equation will be
A. a line parallel to x-axis
B. a line cutting both the axes
C. a line making positive acute angle with x-axis
D. a line parallel to y-axis

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