The graphs of the equations 3x + y - 5 = 0 and 2x - y - 5 = 0 intersect at the point P(α, β). What is the value of (3α + β)?
A. 3
B. 5
C. 4
D. -4
Answer: Option B
Solution (By Examveda Team)
$$\eqalign{ & 3x + y = 5 \cr & \underline {2x - y = 5} \cr & 5x = 10 \cr & x = 2,\,y = - 1 \cr & \left( {\alpha ,\,\beta } \right) = \left( {2,\, - 1} \right) \cr & 3\alpha + \beta = 3 \times 2 - 1 = 5 \cr} $$Related Questions on Coordinate Geometry
In what ratio does the point T(x, 0) divide the segment joining the points S(-4, -1) and U(1, 4)?
A. 1 : 4
B. 4 : 1
C. 1 : 2
D. 2 : 1
A. 2x - y = 1
B. 3x + 2y = 3
C. 2x + y = 2
D. 3x + 5y = 1
If a linear equation is of the form x = k where k is a constant, then graph of the equation will be
A. a line parallel to x-axis
B. a line cutting both the axes
C. a line making positive acute angle with x-axis
D. a line parallel to y-axis

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