The graphs of the equations 7x + 11y = 3 and 8x + y = 15 intersect at the point P, which also lies on the graph of the equation:

Solution (By Examveda Team)

$$\eqalign{ & 7x + 11y = 3\,\,\,\,*1 \cr & \underline {\,8x + y = 15\,} \,\,\,\,\,\underline {\,*11\,} \cr & \,\,7x + 11y = 3 \cr & \,\,88x + 11y = 165 \cr & \underline {\, - \,\,\,\,\,\,\,\,\, - \,\,\,\,\,\,\,\,\,\, - \,\,\,\,\,\,\,\,\,\,} \cr & - 81x = - 162 \cr & x = 2 \cr & y = 15 - 8 \times 2 \cr & y = - 1 \cr} $$ Put value of x and y in options only option 'D' satisfy in this values
3x + 5y = 1
3 × 2 + 5 × (-1) = 1
6 - 5 = 1 = 1 [satisfied]