The horse power transmitted through a pipe is maximum when the ratio of loss of head due to friction and total head supplied is
A. $$\frac{1}{3}$$
B. $$\frac{1}{4}$$
C. $$\frac{1}{2}$$
D. $$\frac{2}{3}$$
Answer: Option A
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A. 22.5 m/sec.
B. 33 m/sec.
C. 40 m/sec.
D. 90 m/sec.
A. the weight of the body
B. more than the weight of the body
C. less than the weight of the body
D. weight of the fluid displaced by the body
The difference of pressure between the inside and outside of a liquid drop is
A. $${\text{p}} = {\text{T}} \times {\text{r}}$$
B. $${\text{p}} = \frac{{\text{T}}}{{\text{r}}}$$
C. $${\text{p}} = \frac{{\text{T}}}{{2{\text{r}}}}$$
D. $${\text{p}} = \frac{{2{\text{T}}}}{{\text{r}}}$$
A. cannot be subjected to shear forces
B. always expands until it fills any container
C. has the same shear stress.at a point regardless of its motion
D. cannot remain at rest under action of any shear force
head loss due to friction (hf)= fLV²/2gD
Total head supplied (H)
When the power transmitted through pipe is maximum then
H - (3fLV²/2gD )=0
(H)-(3hf)=0
H=3hf
So, hf/H=1/3
Please tell the theory behind this answer
Pls explain
How?