The L, S and J quantum numbers corresponding to the ground state electronic configuration of boron (Z = 5) are
A. L = 1, S = $$\frac{1}{2}$$, J = $$\frac{3}{2}$$
B. L = 1, S = $$\frac{1}{2}$$, J = $$\frac{1}{2}$$
C. L = 1, S = $$\frac{3}{2}$$, J = $$\frac{1}{2}$$
D. L = 0, S = $$\frac{3}{2}$$, J = $$\frac{3}{2}$$
Answer: Option B
Join The Discussion