The length of the longest rod that can be placed in a room of dimensions 10 m × 10 m × 5 m is :
A. 15$$\sqrt 3 $$ m
B. 15 m
C. 10$$\sqrt 2 $$ m
D. 5$$\sqrt 3 $$ m
Answer: Option B
Solution (By Examveda Team)
Required length :$$\eqalign{ & = \sqrt {{{\left( {10} \right)}^2} + {{\left( {10} \right)}^2} + {{\left( 5 \right)}^2}} \,m \cr & = \sqrt {225} \,m \cr & = 15\,m \cr} $$
This Question Belongs to Arithmetic Ability >> Volume And Surface Area
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