The length of the longest rod that can be placed in a room of dimensions 10 m × 10 m × 5 m is :

A. 15$$\sqrt 3 $$ m

B. 15 m

C. 10$$\sqrt 2 $$ m

D. 5$$\sqrt 3 $$ m

Answer: Option B

Solution(By Examveda Team)

Required length :
$$\eqalign{ & = \sqrt {{{\left( {10} \right)}^2} + {{\left( {10} \right)}^2} + {{\left( 5 \right)}^2}} \,m \cr & = \sqrt {225} \,m \cr & = 15\,m \cr} $$