The length of the portion of the straight line 3x + 4y = 12 intercepted between the axes is:
A. 5
B. 3
C. 4
D. 7
Answer: Option A
Solution (By Examveda Team)
$$\eqalign{ & 3x + 4y = 12 \cr & \Rightarrow \frac{{3x}}{{12}} + \frac{{4y}}{{12}} = 1 \cr & \Rightarrow \frac{x}{4} + \frac{y}{3} = 1 \cr & \therefore {\text{Length of intercept AB}} = \sqrt {{4^2} + {3^3}} \cr & = \sqrt {25} \cr & = 5{\text{ units}} \cr} $$Related Questions on Coordinate Geometry
In what ratio does the point T(x, 0) divide the segment joining the points S(-4, -1) and U(1, 4)?
A. 1 : 4
B. 4 : 1
C. 1 : 2
D. 2 : 1
A. 2x - y = 1
B. 3x + 2y = 3
C. 2x + y = 2
D. 3x + 5y = 1
If a linear equation is of the form x = k where k is a constant, then graph of the equation will be
A. a line parallel to x-axis
B. a line cutting both the axes
C. a line making positive acute angle with x-axis
D. a line parallel to y-axis

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