The length of the shadow of a vertical pole on the ground is 36 m. If the angle of elevation of the sun at that time is $$\theta $$ such that $$\sec \theta = \frac{{13}}{{12}},$$   then what is the height (in cm) of the pole?

Solution (By Examveda Team)

\[\begin{gathered} \begin{array}{*{20}{c}} {\sec \theta = }&{\frac{{\,\,\,13}}{\begin{gathered} \,\,\,12\,\, \hfill \\ ^{ \times 3} \downarrow \hfill \\ \end{gathered} }} \\ {}&{\,\,\,36} \end{array} \hfill \\ 5{\text{ unit}} \to 5 \times 3 = 15{\text{ m}} \hfill \\ \end{gathered} \]