The moment of inertia of a triangular section (height h, base b) about its base, is
A. $$\frac{{{\text{b}}{{\text{h}}^2}}}{{12}}$$
B. $$\frac{{{{\text{b}}^2}{\text{h}}}}{{12}}$$
C. $$\frac{{{\text{b}}{{\text{h}}^3}}}{{12}}$$
D. $$\frac{{{{\text{b}}^3}{\text{h}}}}{{12}}$$
Answer: Option C
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Comments ( 4 )
A. $$\frac{2}{3}$$
B. $$\frac{3}{2}$$
C. $$\frac{5}{8}$$
D. $$\frac{8}{5}$$
Principal planes are subjected to
A. Normal stresses only
B. Tangential stresses only
C. Normal stresses as well as tangential stresses
D. None of these
A. $$\frac{{\text{M}}}{{\text{I}}} = \frac{{\text{R}}}{{\text{E}}} = \frac{{\text{F}}}{{\text{Y}}}$$
B. $$\frac{{\text{I}}}{{\text{M}}} = \frac{{\text{R}}}{{\text{E}}} = \frac{{\text{F}}}{{\text{Y}}}$$
C. $$\frac{{\text{M}}}{{\text{I}}} = \frac{{\text{E}}}{{\text{R}}} = \frac{{\text{F}}}{{\text{Y}}}$$
D. $$\frac{{\text{M}}}{{\text{I}}} = \frac{{\text{E}}}{{\text{R}}} = \frac{{\text{Y}}}{{\text{F}}}$$
A. $$\frac{{\text{M}}}{{\text{T}}}$$
B. $$\frac{{\text{T}}}{{\text{M}}}$$
C. $$\frac{{2{\text{M}}}}{{\text{T}}}$$
D. $$\frac{{2{\text{T}}}}{{\text{M}}}$$
I for triangle =bh^3/36
At base
I+Ay^2=bh^3/36+1/2*b*h(h/3)^2
=bh^3/12
About its centroid bh^3/36
And
Base bh^3/12
Wrong
BH^3/36 for triangular section