The point of contraflexure is the point where
A. B.M. changes sign
B. B.M. is maximum
C. B.M. is minimum
D. S.F. is zero
Answer: Option A
Solution (By Examveda Team)
The point of contraflexure is the location on a beam where the bending moment (B.M.) changes its sign. This means that the bending moment transitions from positive to negative or vice versa at this point.Key Points:
B.M. changes sign: The point of contraflexure is characterized by a change in the sign of the bending moment, indicating a shift in the direction of bending.
B.M. is maximum or minimum: Maximum or minimum bending moments occur at different points along the beam and are not necessarily at the point of contraflexure.
S.F. is zero: While shear force (S.F.) being zero might be a condition at some points, it is not a defining characteristic of the point of contraflexure. The point of contraflexure specifically involves a change in the bending moment direction.
Join The Discussion
Comments (1)
A. $$\frac{2}{3}$$
B. $$\frac{3}{2}$$
C. $$\frac{5}{8}$$
D. $$\frac{8}{5}$$
Principal planes are subjected to
A. Normal stresses only
B. Tangential stresses only
C. Normal stresses as well as tangential stresses
D. None of these
A. $$\frac{{\text{M}}}{{\text{I}}} = \frac{{\text{R}}}{{\text{E}}} = \frac{{\text{F}}}{{\text{Y}}}$$
B. $$\frac{{\text{I}}}{{\text{M}}} = \frac{{\text{R}}}{{\text{E}}} = \frac{{\text{F}}}{{\text{Y}}}$$
C. $$\frac{{\text{M}}}{{\text{I}}} = \frac{{\text{E}}}{{\text{R}}} = \frac{{\text{F}}}{{\text{Y}}}$$
D. $$\frac{{\text{M}}}{{\text{I}}} = \frac{{\text{E}}}{{\text{R}}} = \frac{{\text{Y}}}{{\text{F}}}$$
A. $$\frac{{\text{M}}}{{\text{T}}}$$
B. $$\frac{{\text{T}}}{{\text{M}}}$$
C. $$\frac{{2{\text{M}}}}{{\text{T}}}$$
D. $$\frac{{2{\text{T}}}}{{\text{M}}}$$

The bending moment at the Free end of a cantilever beam carrying any type of load? (a)minimum (b) maximum (c) equal to on the beam (c) zero