The product of three consecutive even numbers when divided by 8 is 720. The product of their square roots is :
A. $$12\sqrt {10} $$
B. $$24\sqrt {10} $$
C. 120
D. None of these
Answer: Option B
Solution(By Examveda Team)
Let the numbers be x, x + 2 and x + 4Then,
$$\eqalign{ & \Leftrightarrow \frac{{x\left( {x + 2} \right)\left( {x + 4} \right)}}{8} = 720 \cr & \Leftrightarrow x\left( {x + 2} \right)\left( {x + 4} \right) = 5760 \cr & \therefore \sqrt x \times \sqrt {\left( {x + 2} \right)} \times \sqrt {\left( {x + 4} \right)} \cr & = \sqrt {x\left( {x + 2} \right)\left( {x + 4} \right)} \cr & = \sqrt {5760} \cr & = 24\sqrt {10} \cr} $$
Related Questions on Problems on Numbers
If one-third of one-fourth of a number is 15, then three-tenth of that number is:
A. 35
B. 36
C. 45
D. 54
E. None of these
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B. 11
C. 13
D. 15
E. None of these
A. 3
B. 4
C. 9
D. Cannot be determined
E. None of these
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