?
The product of two numbers is 120 and the sum of their square is 289. The sum of the numbers is :
Answer & Solution
Correct Answer:
Option
B
Let the numbers be x and y
Then,
xy = 120 and x2 + y2 = 289
$$\eqalign{ & \therefore {\left( {x + y} \right)^2} \cr & = {x^2} + {y^2} + 2xy \cr & = 289 + 240 \cr & = 529 \cr & \therefore x + y \cr & = \sqrt {529} \cr & = 23 \cr} $$
Then,
xy = 120 and x2 + y2 = 289
$$\eqalign{ & \therefore {\left( {x + y} \right)^2} \cr & = {x^2} + {y^2} + 2xy \cr & = 289 + 240 \cr & = 529 \cr & \therefore x + y \cr & = \sqrt {529} \cr & = 23 \cr} $$
Join the Discussion
Login to post a comment or share your explanation.
Login