The product of two numbers is 120 and the sum of their square is 289. The sum of the numbers is :
A. 20
B. 23
C. 169
D. None of these
Answer: Option B
Solution(By Examveda Team)
Let the numbers be x and yThen,
xy = 120 and x2 + y2 = 289
$$\eqalign{ & \therefore {\left( {x + y} \right)^2} \cr & = {x^2} + {y^2} + 2xy \cr & = 289 + 240 \cr & = 529 \cr & \therefore x + y \cr & = \sqrt {529} \cr & = 23 \cr} $$
Related Questions on Problems on Numbers
If one-third of one-fourth of a number is 15, then three-tenth of that number is:
A. 35
B. 36
C. 45
D. 54
E. None of these
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C. 13
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B. 4
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D. Cannot be determined
E. None of these
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