The ratio between a two-digit number and the sum of the digits of that number is 4 : 1. If the digit in the unit's place is 3 more than the digit in the ten's place, then the number is ?
A. 24
B. 36
C. 63
D. 96
Answer: Option B
Solution(By Examveda Team)
Let the ten's digit be xThen, units digit = x + 3
Number = 10x + (x + 3)
= 11x + 3
Sum of digits = x + (x + 3)
= 2x + 3
$$\eqalign{ & \therefore \frac{{11x + 3}}{{2x + 3}} = \frac{4}{1} \cr & \Leftrightarrow 11x + 3 = 8x + 12 \cr & \Leftrightarrow 3x = 9 \cr & \Leftrightarrow x = 3 \cr} $$
Hence, Required number
= 11x + 3
= 11 × 3 + 3
= 36
Related Questions on Problems on Numbers
If one-third of one-fourth of a number is 15, then three-tenth of that number is:
A. 35
B. 36
C. 45
D. 54
E. None of these
A. 9
B. 11
C. 13
D. 15
E. None of these
A. 3
B. 4
C. 9
D. Cannot be determined
E. None of these
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