The ratio of the area of cross-section of a circular section to the area of its core, is
A. 4
B. 8
C. 12
D. 16
Answer: Option D
This Question Belongs to Civil Engineering >> Theory Of Structures
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A. $$\frac{2}{3}$$
B. $$\frac{3}{2}$$
C. $$\frac{5}{8}$$
D. $$\frac{8}{5}$$
Principal planes are subjected to
A. Normal stresses only
B. Tangential stresses only
C. Normal stresses as well as tangential stresses
D. None of these
A. $$\frac{{\text{M}}}{{\text{I}}} = \frac{{\text{R}}}{{\text{E}}} = \frac{{\text{F}}}{{\text{Y}}}$$
B. $$\frac{{\text{I}}}{{\text{M}}} = \frac{{\text{R}}}{{\text{E}}} = \frac{{\text{F}}}{{\text{Y}}}$$
C. $$\frac{{\text{M}}}{{\text{I}}} = \frac{{\text{E}}}{{\text{R}}} = \frac{{\text{F}}}{{\text{Y}}}$$
D. $$\frac{{\text{M}}}{{\text{I}}} = \frac{{\text{E}}}{{\text{R}}} = \frac{{\text{Y}}}{{\text{F}}}$$
A. $$\frac{{\text{M}}}{{\text{T}}}$$
B. $$\frac{{\text{T}}}{{\text{M}}}$$
C. $$\frac{{2{\text{M}}}}{{\text{T}}}$$
D. $$\frac{{2{\text{T}}}}{{\text{M}}}$$
Dia of Core of circle = d/4.
Dia of Circle = d.
Area of Core/Area of Circle = 1/16 will get.
assuming non eccentric ccondition
e=D/8(Radius of core)
area of column=(22/7)xD^2/4................Eq 1
area of core=(22/7)X r^2
area of core= 22/7x D^2/64.....................Eq2
now dividing eq1/eq 2
we get 16
Area or colum = pi x D2/4
Radius of core, r = D/8
Area of core = pi x r2 = pi x (D2)/64
Ratio , pi x D2/4 / pi x (D2)/64 = 64/4 =16
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