The self inductances of two coils are 8 mH and 18 mH. If the coefficient of coupling is 0.5, the mutual inductance of the coils is
A. 4 mH
B. 5 mH
C. 6 mH
D. 12 mH
Answer: Option C
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K=M/√L1L2
M=K×√L1L2
M=0.5×√8×18
M=6
M=L× Sq.Root(M1xM2)
E.g. M=0.5 x Sq.root(8×18)
M=0.5 x 12 ==> 6
M = k * sqrt( L1 * L2),
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