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The speed of A and B are in the ratio 3 : 4. A takes 20 minutes more than B to reach a destination. Time in which A reach the destination?
Answer & Solution
Correct Answer:
Option
A
Ratio of speed = 3 : 4
Ratio of time taken = 4 : 3 (As Speed ∝ $$\frac{1}{{{\text{Time}}}},$$ When distance remains constant.)
Let time taken by A and B be 4x and 3x hour respectively.
Then,
4x - 3x = $$\frac{{20}}{{60}}$$
Or, x = $$\frac{{1}}{{3}}$$
Hence, time taken by A = 4x hours = 4 × $$\frac{1}{3}$$ = $$1\frac{1}{3}$$ hours.
Ratio of time taken = 4 : 3 (As Speed ∝ $$\frac{1}{{{\text{Time}}}},$$ When distance remains constant.)
Let time taken by A and B be 4x and 3x hour respectively.
Then,
4x - 3x = $$\frac{{20}}{{60}}$$
Or, x = $$\frac{{1}}{{3}}$$
Hence, time taken by A = 4x hours = 4 × $$\frac{1}{3}$$ = $$1\frac{1}{3}$$ hours.
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