The speeds of John and Max are 30 km/hr and 40 km/hr. Initially Max is at a place L and Jhon is at a place M. The distance between L and M is 650 kms. John started his journey 3 hours earlier than Max to meet each other. If they meet each other at a place P somewhere between L and M, then the distance between P and M is :
A. 220 kms
B. 250 kms
C. 330 kms
D. 320 kms
Answer: Option C
Solution(By Examveda Team)
Speed of John = 30 km/hSpeed of Max = 40 km/h
Distance between L and M = 650 km
Distance travelled by john in 3 hours
= 30 x 3
= 90 km
Time taken by Max and John to travel remaining
= 650 - 90
= 560 km
$$\eqalign{ & = \frac{{560}}{{40 + 30}} \cr & = \frac{{560}}{{70}} \cr & = 8\,{\text{hours}} \cr} $$
Distance travel by John to reach point
P = 8 × 30 = 240 km
Distance between P and M
= 240 + 90
= 330 km
Related Questions on Speed Time and Distance
A. 48 min.
B. 60 min.
C. 42 min.
D. 62 min.
E. 66 min.
A. 262.4 km
B. 260 km
C. 283.33 km
D. 275 km
E. None of these
A. 4 hours
B. 4 hours 30 min.
C. 4 hours 45 min.
D. 5 hours
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