The value of compression index for a remoulded sample whose liquid limit is 50% is

Riju Chakraborty 3 months ago

For a remoulded clay, Skempton’s empirical relation is:
Cc = 0.007(WL - 10)
Given liquid limit:
WL = 50%
Therefore
Cc = 0.007(50-10)
=0.007*40
=0.28

Snehasish Nath 7 months ago

Cc = 0.007*(wL-10) for remoulded clay
Cc = 0.009*(wL-10) for undisturbed clay

Vijay Kumar 5 years ago

.301

Àbíñâsh Sãhõó 5 years ago

0.009×(50-20)=0.28

Mohsin Qureshi 6 years ago

Cc=0.007(LL-7)=0.007(50-7)=0.28

Shubham Gour 6 years ago

0.007×(50-10)=0.28

Myexam B 7 years ago

Compression Index
=0.007(WL-10) for remoulded soil
And
=0.009(WL-10) for undisturbed soil

Legendary Civilians 7 years ago

For remoulded clay
Cc=0.007(LL-10)
Answer: 0.28

Shadab Alam 7 years ago

For remoulded case
Cc=0.007(wl-7)
Cc=0.301

Al Amin 7 years ago

Cc =0.009(LL-10)
Cc = 0.36 will be the answer

Suraj Bangar 8 years ago

explain