The value of mass density in kg.sec2m4 for water at 0°C is
A. 1
B. 1000
C. 100
D. 101.9
Answer: Option D
This Question Belongs to Civil Engineering >> Hydraulics And Fluid Mechanics
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A. 22.5 m/sec.
B. 33 m/sec.
C. 40 m/sec.
D. 90 m/sec.
A. the weight of the body
B. more than the weight of the body
C. less than the weight of the body
D. weight of the fluid displaced by the body
The difference of pressure between the inside and outside of a liquid drop is
A. $${\text{p}} = {\text{T}} \times {\text{r}}$$
B. $${\text{p}} = \frac{{\text{T}}}{{\text{r}}}$$
C. $${\text{p}} = \frac{{\text{T}}}{{2{\text{r}}}}$$
D. $${\text{p}} = \frac{{2{\text{T}}}}{{\text{r}}}$$
A. cannot be subjected to shear forces
B. always expands until it fills any container
C. has the same shear stress.at a point regardless of its motion
D. cannot remain at rest under action of any shear force
1 Newton value=1/9.81
water =1000
Density = (1/9.81)x(1000)
= 101.9(Ans)
2nd last step is not correct
1N =1/9.81 kgf not kg
Dimensions not correct
F =m.a
N= kg.m/sec^2
Then , kg = N.sec^2/m
According to the question:-
Water Density=1000 Kg/m^3
1000 * N.sec^2/m^4
1 Newton equal to 1/9.81 or 0.10193 kg
Then 1000 * 0.10193kg.sec^2/m^4 = 101.9kg.sec^2/m^4
How