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The volume of a right circular cylinder, 14 cm in height is equal to that of a cube whose edge is 11 cm. The radius of the base of the cylinder is :
Answer & Solution
Correct Answer:
Option
B
Volume of the cylinder :
= Volume of the cube
= (11)3 cm3
= 1331 cm3
Let the radius of the base be r cm
Then,
$$\eqalign{ & \frac{{22}}{7} \times {r^2} \times 14 = 1331 \cr & \Rightarrow {r^2} = \frac{{1331}}{{44}} = \frac{{121}}{4} \cr & \Rightarrow r = \frac{{11}}{2} \cr & \Rightarrow r = 5.5 \cr} $$
= Volume of the cube
= (11)3 cm3
= 1331 cm3
Let the radius of the base be r cm
Then,
$$\eqalign{ & \frac{{22}}{7} \times {r^2} \times 14 = 1331 \cr & \Rightarrow {r^2} = \frac{{1331}}{{44}} = \frac{{121}}{4} \cr & \Rightarrow r = \frac{{11}}{2} \cr & \Rightarrow r = 5.5 \cr} $$
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