The volume of two spheres are in the ratio of 64 : 27. The ratio p their surface areas is :

Solution(By Examveda Team)

Let their radii be R and r
Then,
$$\eqalign{ & \frac{{\frac{4}{3}\pi {R^3}}}{{\frac{4}{3}\pi {r^3}}} = \frac{{64}}{{27}} \cr & \Rightarrow {\left( {\frac{R}{r}} \right)^3} = \frac{{64}}{{27}} \cr & \Rightarrow {\left( {\frac{R}{r}} \right)^3} = {\left( {\frac{4}{3}} \right)^3} \cr & \Rightarrow \frac{R}{r} = \frac{4}{3} \cr} $$
Ratio of surface areas :
$$\eqalign{ & = \frac{{4\pi {R^2}}}{{4\pi {r^2}}} = {\left( {\frac{R}{r}} \right)^2} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = {\left( {\frac{4}{3}} \right)^2} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{{16}}{9} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 16:9 \cr} $$