Three circle of radius 3.5 cm are placed in such a way that each circle touches the other two. The area of the portion enclosed by the circles is :
A. 1.967 cm2
B. 1.975 cm2
C. 19.67 cm2
D. 21.21 cm2
Answer: Option A
Solution(By Examveda Team)
Required area = (Area of an equilateral Δ of side 7 cm) - (3 × Area of sector with θ = 60° and r = 3.5 cm)$$ = \left[ {\left( {\frac{{\sqrt 3 }}{4} \times 7 \times 7} \right) - \left( {3 \times \frac{{22}}{7} \times 3.5 \times 3.5 \times \frac{{60}}{{360}}} \right)} \right]c{m^2}$$
$$\eqalign{ & = \left( {\frac{{49\sqrt 3 }}{4} - 11 \times 0.5 \times 3.5} \right)c{m^2} \cr & = (21.217 - 19.25)c{m^2} \cr & = 1.967\,c{m^2} \cr} $$
Related Questions on Area
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D. 307200 m2
E. None of these
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B. 2.02%
C. 4%
D. 4.04%
E. None of these
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B. 18 cm
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D. Data inadequate
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The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is:
A. 40%
B. 42%
C. 44%
D. 46%
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