Three plots having areas 110, 130 and 190 square metres are to be subdivided into flower beds of equal size. If the breadth of a bed is 2 metres, the maximum length of a bed van be :
A. 5 m
B. 11 m
C. 13 m
D. 19 m
Answer: Option A
Solution(By Examveda Team)
Maximum possible size of a flower bed := (H.C.F. of 110, 130, 190) sq. m
= 10 sq. m
∴ Maximum possible length = $$\left( {\frac{{10}}{2}} \right)$$ m = 5 m
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D. 307200 m2
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E. None of these
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The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is:
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C. 44%
D. 46%
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