To obtain photographs of an area of 1000 m average elevation, on scale 1 : 30,000, with a camera of 30 cm focal length, the flying height is
A. 4000 m
B. 5000 m
C. 6000 m
D. 7000 m
Answer: Option C
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A. 750 mm × 900 mm
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IT MUST BE 8,000. (1/30,000) ÷ ((30cm/100m)/H-1000m) = H = 8,000
scale = f/H-h
f: focal length= 30cm=.3m
h=elevation height=1000m
H=height of flight=?
1/30000=.3/(H-1000)
H=8000
1000 x 30 =30000
(30000 + 30000) / 10
60000/10
6000
H=10000
H=10000
1000/(3.3^( - 5 * 0.3))=5994.74
Ans 5994
H= 10,000
Isn't it H=10,000?
How to solve
How to solve this problem ??Pls explain
Scale=1:30,000
Focal length=30cm=0.3m
Flying height =X+1000
We have ,
Scale =focal length of camera/flying height above ground level
(1/30000)=(0.3/X+1000)
X=8000 from my calculation
No the answer is 10000
Explanation:
Scale= f/(H-h)
Where H is height of exposure station or plane
h - height of ground above mean sea level
1/30000= 30x10-2/(H-1000)
H= 30000x.3+ 1000
H= 10000
how to solve this problem ?
Please give explanation.