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To obtain photographs of an area of 1000 m average elevation, on scale 1 : 30,000, with a camera of 30 cm focal length, the flying height is

A. 4000 m

B. 5000 m

C. 6000 m

D. 7000 m

Answer: Option C


This Question Belongs to Civil Engineering >> Surveying

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Comments ( 14 )

  1. Rose Ann
    Rose Ann :
    5 months ago

    IT MUST BE 8,000. (1/30,000) ÷ ((30cm/100m)/H-1000m) = H = 8,000

  2. Hanif Ullah
    Hanif Ullah :
    8 months ago

    scale = f/H-h
    f: focal length= 30cm=.3m
    h=elevation height=1000m
    H=height of flight=?
    1/30000=.3/(H-1000)
    H=8000

  3. Mister Maskulado
    Mister Maskulado :
    1 year ago

    1000 x 30 =30000
    (30000 + 30000) / 10
    60000/10
    6000

  4. Elnora Acoba
    Elnora Acoba :
    2 years ago

    H=10000

  5. Elnora Acoba
    Elnora Acoba :
    2 years ago

    H=10000

  6. Gaming Outlaw
    Gaming Outlaw :
    2 years ago

    1000/(3.3^( - 5 * 0.3))=5994.74

  7. Gaming Outlaw
    Gaming Outlaw :
    2 years ago

    Ans 5994

  8. Louie Jake
    Louie Jake :
    3 years ago

    H= 10,000

  9. Louie Jake
    Louie Jake :
    3 years ago

    Isn't it H=10,000?

  10. Sandya Rani
    Sandya Rani :
    3 years ago

    How to solve

  11. Suga Shini
    Suga Shini :
    3 years ago

    How to solve this problem ??Pls explain

  12. Sakar Kc
    Sakar Kc :
    3 years ago

    Scale=1:30,000
    Focal length=30cm=0.3m
    Flying height =X+1000
    We have ,
    Scale =focal length of camera/flying height above ground level
    (1/30000)=(0.3/X+1000)
    X=8000 from my calculation

  13. Chirag Raghu
    Chirag Raghu :
    3 years ago

    No the answer is 10000
    Explanation:
    Scale= f/(H-h)
    Where H is height of exposure station or plane
    h - height of ground above mean sea level

    1/30000= 30x10-2/(H-1000)
    H= 30000x.3+ 1000
    H= 10000

  14. Kailash Meena
    Kailash Meena :
    4 years ago

    how to solve this problem ?
    Please give explanation.

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