Two boys A and B start at the same time to ride from Delhi to Meerut, 60 km away. A travels 4 km an hours slower than B, B reaches Meerut and at once turns back meeting A, 12 km from Meerut. A's rate was :
A. 4 km/hr
B. 8 km/hr
C. 12 km/hr
D. 16 km/hr
Answer: Option B
Solution(By Examveda Team)
Let A's speed = x km/hrThen, B's speed = (x + 4) km/hr
Clearly, time taken by B to cover (60 + 12) i.e., 72 km
= Time taken by A to cover (60 - 12) i.e., 48 km
$$\eqalign{ & \therefore \frac{{72}}{{x + 4}} = \frac{{48}}{x} \cr & \Rightarrow 72x = 48x + 192 \cr & \Rightarrow 24x = 192 \cr & \Rightarrow x = 8 \cr} $$
Hence, A's speed = 8 km/hr
Related Questions on Speed Time and Distance
A. 48 min.
B. 60 min.
C. 42 min.
D. 62 min.
E. 66 min.
A. 262.4 km
B. 260 km
C. 283.33 km
D. 275 km
E. None of these
A. 4 hours
B. 4 hours 30 min.
C. 4 hours 45 min.
D. 5 hours
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