Two persons A and B start simultaneously from P and Q respectively. A meets B at a distance of 60m from P. After A reaches Q and B reaches P, they turn around and start walking in opposite direction, now B meets A at a distance of 40m from Q. Find distance between P and Q?
A. 160 m
B. 100 m
C. 140 m
D. 105 m
E. None of These
Answer: Option C
Solution(By Examveda Team)
P_____60m___R__Xm____40m____Q Total distance = 100 + X Initially, A traveled 60m and B traveled (40 + X)m. Since time is same. So, Speed ∝ Distance. $$\frac{{{{\text{S}}_{\text{a}}}}}{{{{\text{S}}_{\text{b}}}}} = \frac{{60}}{{40 + {\text{X}}}}$$ Second time, So, now total distance traveled by A = 100 + X + 40 Total distance traveled by B = 100 + X + 60 + X These will be in the ratio of Speed of A and B Thus, $$\frac{{{{\text{S}}_{\text{a}}}}}{{{{\text{S}}_{\text{b}}}}} = \frac{{60}}{{40 + {\text{X}}}} = \frac{{100 + {\text{X}} + 40}}{{100 + {\text{X}} + 60 + {\text{X}}}}$$ X = 40 Thus Total distance = 100 + X = 100 + 40 = 140 mJoin The Discussion
Comments ( 1 )
Related Questions on Speed Time and Distance
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Cannot understand the solution