Two trains are moving in the opposite direction at the speed...

Home / Arithmetic Ability / Speed Time And Distance / Question

Examveda

Two trains are moving in the opposite direction at the speed of 48 km/hr and 60 km/hr respectively. The time taken by the slower train to cross a man sitting in the faster train is 12 seconds. What is the length of the slower train?

A. 480 metres

B. 720 metres

C. 180 metres

D. 360 metres

Answer: Option D

Solution (By Examveda Team)

$$\eqalign{ & {T_L} = \left( {48 + 60} \right) \times \frac{5}{{18}} \times 12 \cr & = 108 \times \frac{5}{3} \times 2 \cr & = 360 \cr} $$

This Question Belongs to Arithmetic Ability >> Speed Time And Distance

Join The Discussion

Related Questions on Speed Time and Distance

Two buses start from a bus terminal with a speed of 20 km/h at interval of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at interval of 8 minutes?

A. 3 km/h

B. 4 km/h

C. 5 km/h

D. 7 km/h

View Answer

View Answer

Walking $$\frac{3}{4}$$ of his normal speed, Rabi is 16 minutes late in reaching his office. The usual time taken by him to cover the distance between his home and office:

A. 48 min.

B. 60 min.

C. 42 min.

D. 62 min.

E. 66 min.

View Answer

View Answer

Two trains for Mumbai leave Delhi at 6 am and 6.45 am and travel at 100 kmph and 136 kmph respectively. How many kilometers from Delhi will the two trains be together:

A. 262.4 km

B. 260 km

C. 283.33 km

D. 275 km

E. None of these

View Answer

View Answer

A man takes 6 hours 15 minutes in walking a distance and riding back to starting place. He could walk both ways in 7 hours 45 minutes. The time taken by him to ride back both ways is:

A. 4 hours

B. 4 hours 30 min.

C. 4 hours 45 min.

D. 5 hours

View Answer

View Answer

More Related Questions on Speed Time and Distance