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Two trains are running with speed 30 km/hr and 58 km/hr in the same direction, a man in the slower train passes the faster train in 18 sec. The length (in metres) of the faster train is :
Answer & Solution
Correct Answer:
Option
D
Int e question it is given that, a man who sit in the slower train cross the faster train it means faster train cross the man 18 sec.
⇒ Relative speed of faster train and man in the same direction
= (58 - 30)
= 28 kmph
So, the distance covered by faster train in 18 sec :
= 28 kmph × 18 sec
= 28 × $$\frac{5}{18}$$ × 18
= 140 metres
⇒ Relative speed of faster train and man in the same direction
= (58 - 30)
= 28 kmph
So, the distance covered by faster train in 18 sec :
= 28 kmph × 18 sec
= 28 × $$\frac{5}{18}$$ × 18
= 140 metres
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