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Two trains of equal length, running in opposite directions, pass a pole in 18 and 12 seconds. The trains will cross each other in:

A. 14.4 seconds

B. 15.5 seconds

C. 18.8 seconds

D. 20.2 seconds

Answer: Option A

Solution(By Examveda Team)

Let length of each train be x meter.
Then, speed of 1st train = $$\frac{x}{{18}}$$ m/sec
Speed of 2nd train = $$\frac{x}{{12}}$$ m/sec
Now,
When both trains cross each other, time taken
$$\eqalign{ & = {\frac{{2x}}{{ { {\frac{x}{{18}}} + {\frac{x}{{12}}} } }}} \cr & = \frac{{2x}}{{ {\frac{{ {2x + 3x} }}{{36}}} }} \cr & = \frac{{2x \times 36}}{{5x}} \cr & = \frac{{72}}{5} \cr & = 14.4\,\,{\text{seconds}} \cr} $$

This Question Belongs to Arithmetic Ability >> Speed Time And Distance

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Comments ( 1 )

  1. Jagadeesh Jagadish
    Jagadeesh Jagadish :
    6 years ago

    Nice explanation

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