Two trains start from stations A and B and travel towards each other at a speed of 50 kmph and 60 kmph respectively. A the time of their meeting, the second train had travelled 120 km more then the first. The distance between A and B is :

Solution (By Examveda Team)

At the time of meeting, let the distance travelled by the first train be x km.
Then, discount covered by the second train = (x + 120) km
$$\eqalign{ & \therefore \frac{x}{{50}} = \frac{{x + 120}}{{60}} \cr & \Leftrightarrow 60x = 50x + 6000 \cr & \Leftrightarrow 10x = 6000 \cr & \Leftrightarrow x = 600 \cr} $$
So, distance between A and B
= (x + x + 12) km
= 1320 km