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‘u1’ and ‘u2’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v1’ and ‘v2’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by

A. $${\text{e}} = \frac{{{{\text{v}}_1} - {{\text{v}}_2}}}{{{{\text{u}}_2} - {{\text{u}}_1}}}$$

B. $${\text{e}} = \frac{{{{\text{u}}_2} - {{\text{u}}_1}}}{{{{\text{v}}_1} - {{\text{v}}_2}}}$$

C. $${\text{e}} = \frac{{{{\text{v}}_2} - {{\text{v}}_1}}}{{{{\text{u}}_1} - {{\text{u}}_2}}}$$

D. $${\text{e}} = \frac{{{{\text{v}}_1} - {{\text{v}}_2}}}{{{{\text{u}}_2} + {{\text{u}}_1}}}$$

Answer: Option C


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Related Questions on Applied Mechanics and Graphic Statics

The resultant of two forces P and Q acting at an angle $$\theta $$, is

A. $${{\text{P}}^2} + {{\text{Q}}^2} + 2{\text{P}}\sin \theta $$

B. $${{\text{P}}^2} + {{\text{Q}}^2} + 2{\text{PQ}}\cos \theta $$

C. $${{\text{P}}^2} + {{\text{Q}}^2} + 2{\text{PQ}}\tan \theta $$

D. $$\sqrt {{{\text{P}}^2} + {{\text{Q}}^2} + 2{\text{PQ}}\cos \theta } $$

E. $$\sqrt {{{\text{P}}^2} + {{\text{Q}}^2} + 2{\text{PQ}}\sin \theta } $$