Walking at 60% of his usual speed, a man reaches his destination 1 hour 40 minutes late. His usual time (in hours) to reach the destination is:
A. $$3\frac{1}{4}$$
B. $$2\frac{1}{2}$$
C. $$3\frac{1}{8}$$
D. $$2\frac{1}{4}$$
Answer: Option B
Solution (By Examveda Team)
$$60\% = \frac{3}{5}$$Let the speed of the man be 5x
60% of the speed = 5x × $$\frac{3}{5}$$ = 3x
Ratio of speed of man before and after = 5x : 3x
As we know, speed is inversely proportional to time.
Time ratio of man before and after = 3x : 5x
According to the question
5x - 3x = 1 hr 40 min
5x - 3x = $$\left( {1 + \frac{{40}}{{60}}} \right){\text{hr}}$$
2x = $$\frac{5}{3}$$
x = $$\frac{5}{{3 \times 2}}$$
x = $$\frac{5}{6}$$ hr
Required time = 3x = 3 × $$\frac{5}{6}$$ = $$2\frac{1}{2}$$ hr
This Question Belongs to Arithmetic Ability >> Speed Time And Distance
Join The Discussion