Water flows out through a circular pipe whose internal diameter is 2 cm, at the rate of 6 metres per second into a cylindrical tank, the radius of whose base is 60 cm. By how much will the level of water rise in 30 minutes ?

Solution (By Examveda Team)

Volume of water flown through the pipe in 30 min :
$$\eqalign{ & = \left[ {\left( {\pi \times 0.01 \times 0.01 \times 6} \right) \times 30 \times 60} \right]{m^3} \cr & = \left( {1.08\pi } \right){m^3} \cr} $$
Let the rise in level of water be h metres
Then,
$$\eqalign{ & \pi \times 0.6 \times 0.6 \times h = 1.08\pi \cr & \Rightarrow h = \left( {\frac{{1.08}}{{0.6 \times 0.6}}} \right) \cr & \Rightarrow h = 3\,m \cr} $$