What is the area (in sq. units) of the triangle formed by the graphs of the equations 2x + 5y - 12 = 0, x + y = 3 and y = 0?
A. 3
B. 2
C. 5
D. 6
Answer: Option A
Solution (By Examveda Team)

2x + 5y - 12 = 0
x + y = 3
at y = 0
(3, 0), (6, 0)
at x = 0
(0, 2.4)(0, 3)
Area of Δ = $$\frac{1}{2}$$ × 3 × 2 = 3
Related Questions on Coordinate Geometry
In what ratio does the point T(x, 0) divide the segment joining the points S(-4, -1) and U(1, 4)?
A. 1 : 4
B. 4 : 1
C. 1 : 2
D. 2 : 1
A. 2x - y = 1
B. 3x + 2y = 3
C. 2x + y = 2
D. 3x + 5y = 1
If a linear equation is of the form x = k where k is a constant, then graph of the equation will be
A. a line parallel to x-axis
B. a line cutting both the axes
C. a line making positive acute angle with x-axis
D. a line parallel to y-axis

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