What is the slope of the line perpendicular to the line passing through the points (-5, 1) and (-2, 0)?
A. -3
B. 3
C. $$ - \frac{1}{3}$$
D. $$\frac{1}{3}$$
Answer: Option B
Solution (By Examveda Team)
Slope of the line passing through the point (-5, 1) & (-2, 0)$${m_1} = \frac{{0 - 1}}{{ - 2 - \left( { - 5} \right)}} = \frac{{ - 1}}{3}\,\,\,\,\,\left[ {m = \frac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}} \right]$$
Slope of the 1st line $$ = \frac{{ - 1}}{{{m_1}}} = \frac{{ - 1}}{{\left( {\frac{{ - 1}}{3}} \right)}} = 3$$
(∴ If 2 lines are ⊥ then their slope m1 × m2 = -1)
Related Questions on Coordinate Geometry
In what ratio does the point T(x, 0) divide the segment joining the points S(-4, -1) and U(1, 4)?
A. 1 : 4
B. 4 : 1
C. 1 : 2
D. 2 : 1
A. 2x - y = 1
B. 3x + 2y = 3
C. 2x + y = 2
D. 3x + 5y = 1
If a linear equation is of the form x = k where k is a constant, then graph of the equation will be
A. a line parallel to x-axis
B. a line cutting both the axes
C. a line making positive acute angle with x-axis
D. a line parallel to y-axis

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