What would be the equation of the line, which intercepts x-axis at -5 and is perpendicular to the line y = 2x + 3?
A. x - 2y = -5
B. x + 2y = 5
C. x + 2y = -5
D. x - 2y = 5
Answer: Option C
Solution (By Examveda Team)
Slope of line y = mx + c is my = 2x + c, slope (m1) = 2
Lines are perpendicular to each other $${m_1} = \frac{{ - 1}}{{{m_2}}}$$
Slope of perpendicular line $$\left( {{m_2}} \right) = \frac{{ - 1}}{2}$$
on x axis y = 0
Equation of line which passes through (-5, 0)
(y - y1) = slope (m2)(x - x1)
y - 0 = $$\frac{{ - 1}}{2}$$ (x + 5)
2y = -x - 5
x + 2y = -5
Related Questions on Coordinate Geometry
In what ratio does the point T(x, 0) divide the segment joining the points S(-4, -1) and U(1, 4)?
A. 1 : 4
B. 4 : 1
C. 1 : 2
D. 2 : 1
A. 2x - y = 1
B. 3x + 2y = 3
C. 2x + y = 2
D. 3x + 5y = 1
If a linear equation is of the form x = k where k is a constant, then graph of the equation will be
A. a line parallel to x-axis
B. a line cutting both the axes
C. a line making positive acute angle with x-axis
D. a line parallel to y-axis

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