When a body of mass M1 is hanging freely and another of mass M2 lying on a smooth inclined plane ($$\alpha $$) are connected by a light index tensile string passing over a smooth pulley, the acceleration of the body of mass M1, will be given by
A. $$\frac{{{\text{g}}\left( {{{\text{M}}_1} + {{\text{M}}_2}\sin \alpha } \right)}}{{{{\text{M}}_1} + {{\text{M}}_2}}}{\text{m/sec}}$$
B. $$\frac{{{\text{g}}\left( {{{\text{M}}_1} - {{\text{M}}_2}\sin \alpha } \right)}}{{{{\text{M}}_1} + {{\text{M}}_2}}}{\text{m/se}}{{\text{c}}^2}$$
C. $$\frac{{{\text{g}}\left( {{{\text{M}}_2} + {{\text{M}}_1}\sin \alpha } \right)}}{{{{\text{M}}_1} + {{\text{M}}_2}}}{\text{m/se}}{{\text{c}}^2}$$
D. $$\frac{{{\text{g}}\left( {{{\text{M}}_2} \times {{\text{M}}_1}\sin \alpha } \right)}}{{{{\text{M}}_2} - {{\text{M}}_1}}}{\text{m/se}}{{\text{c}}^2}$$
Answer: Option B
In case of S.H.M. the period of oscillation (T), is given by
A. $${\text{T}} = \frac{{2\omega }}{{{\pi ^2}}}$$
B. $${\text{T}} = \frac{{2\pi }}{\omega }$$
C. $${\text{T}} = \frac{2}{\omega }$$
D. $${\text{T}} = \frac{\pi }{{2\omega }}$$
The angular speed of a car taking a circular turn of radius 100 m at 36 km/hr will be
A. 0.1 rad/sec
B. 1 rad/sec
C. 10 rad/sec
D. 100 rad/sec
A body is said to move with Simple Harmonic Motion if its acceleration, is
A. Always directed away from the centre, the point of reference
B. Proportional to the square of the distance from the point of reference
C. Proportional to the distance from the point of reference and directed towards it
D. Inversely proportion to the distance from the point of reference
The resultant of two forces P and Q acting at an angle $$\theta $$, is
A. $${{\text{P}}^2} + {{\text{Q}}^2} + 2{\text{P}}\sin \theta $$
B. $${{\text{P}}^2} + {{\text{Q}}^2} + 2{\text{PQ}}\cos \theta $$
C. $${{\text{P}}^2} + {{\text{Q}}^2} + 2{\text{PQ}}\tan \theta $$
D. $$\sqrt {{{\text{P}}^2} + {{\text{Q}}^2} + 2{\text{PQ}}\cos \theta } $$
E. $$\sqrt {{{\text{P}}^2} + {{\text{Q}}^2} + 2{\text{PQ}}\sin \theta } $$
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