When principal = Rs. S, rate of interest = 2r % p.a., then a person will get after 3 years at compound interest = ?
A. $${\text{Rs}}{\text{. }}\frac{{6{\text{Sr}}}}{{100}}$$
B. $${\text{Rs}}{\text{. S}}{\left( {1 + \frac{{\text{r}}}{{50}}} \right)^3}$$
C. $${\text{Rs}}{\text{. S}}{\left( {1 + \frac{{\text{r}}}{{100}}} \right)^3}$$
D. $${\text{Rs}}{\text{. 3S}}{\left( {1 + \frac{{\text{r}}}{{100}}} \right)^3}$$
Answer: Option B
Solution(By Examveda Team)
$$\eqalign{ & {\text{According to the question}} \cr & {\text{Principal = Rs S}} \cr & {\text{Rate }}\% {\text{ = 2r}}\,\% {\text{ p}}{\text{.a}}{\text{.}} \cr & {\text{Time = 3 years}} \cr & \therefore {\text{A = P}}{\left( {1 + \frac{{\text{r}}}{{100}}} \right)^T} \cr & \Leftrightarrow {\text{A = S}}{\left( {1 + \frac{{{\text{2r}}}}{{100}}} \right)^3} \cr & \Leftrightarrow {\text{A = S}}{\left( {1 + \frac{{\text{r}}}{{50}}} \right)^3} \cr} $$This Question Belongs to Arithmetic Ability >> Compound Interest
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