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This question belongs to Electrical Engineering Ohms Law
Ohms Law
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You are measuring the current in a circuit that is operated on an 18 V battery. The ammeter reads 40 mA. Later you notice the current has dropped to 20 mA. How much has the voltage changed?

Answer & Solution
Correct Answer: Option A
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1 Comment
Mono Alajmi
Mono Alajmi 2 years ago
R= 18/40mA =0.45 K ohm

V2= I 2 * R = 20mA * 0.45K ohm = 9 V