Find the missing number: ²/_√5, ³/₅, ⁴/_5√5, ⁵/₂₅, ?

A. ⁶/_5√5

B. ⁶/_25√5

C. ⁶/₁₂₅

D. ⁷/₂₅

Answer: Option B

Solution(By Examveda Team)

Clearly, the numerators of the given fractions are consecutive natural numbers. So, the numerator of the missing fraction should be 6. Also, the denominator of each fraction is multiplied by √5 to obtain the denominator of the next fraction. So. the denominator of the missing fraction should be 25√5. Hence,the missing term is ⁶/_25√5