60 kg of an alloy A is mixed with 100 kg of alloy B. If alloy A has lead and tin in the ratio 3 : 2 and alloy B has tin and copper in the ratio 1 : 4, the amount of tin in the new alloy is -
A. 44 kg
B. 53 kg
C. 80 kg
D. 24 kg
Answer: Option A
Solution(By Examveda Team)
Quantity of tin in 60 kg of A$$\eqalign{ & = \left( {60 \times \frac{2}{5}} \right)\,{\text{kg}} \cr & = 24\,{\text{kg}} \cr} $$
Quantity of tin in 100 kg of B
$$\eqalign{ & = \left( {100 \times \frac{1}{5}} \right)\,{\text{kg}} \cr & = 20\,{\text{kg}} \cr} $$
∴ Quantity of tin in the new alloy
= (24 + 20) kg
= 44 kg
Related Questions on Alligation
A. $$\frac{{1}}{{2}}$$ kg
B. $$\frac{{1}}{{8}}$$ kg
C. $$\frac{{3}}{{14}}$$ kg
D. $$\frac{{7}}{{9}}$$ kg
A. 81 litres
B. 71 litres
C. 56 litres
D. 50 litres
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