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In what ratio must a mixture of 30% alcohol strength be mixed with that of 50% alcohol strength so as to get a mixture of 45% alcohol strength?
Answer & Solution
Correct Answer:
Option
B
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Login30 ···································· 50
···················· 45 ····················
5 : 15 or 1 : 3 (Ans.)
or
30x + 50y = 45(x+y)
⇒ 30x + 50y = 45x + 45y
⇒ 15x = 5y
⇒x/y = 1/3
So, x : y = 1 : 3
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