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An alloy contains zinc, copper and tin in the ratio 2 : 3 : 1 and another contains copper, tin and lead in the ratio 5 : 4 : 3. If equal weights of both alloys are melted together to form a third alloy, then the weight of lead per kg in new alloy will be:
Answer & Solution
Correct Answer:
Option
B
Ratio of Zinc, Copper and Tin is given as,
Z : C : T = 2 : 3 : 1.
Now, let the first alloy be 12 kg (taken as 4 kg Zinc, 6 kg Copper and 2 Kg Lead).
Weight of second alloy = 12 kg as, C : T : L = 5 : 4 : 3. (taken as 5 kg Copper, 4 kg Tin and 3 Kg Lead.)
Alloys are mixed together to form third alloy. Then the ratio of content in it,
Z : C : T : L = 4 : (6 + 5) : (2 + 4) : 3
Weight of third alloy = 12 + 12 = 24 Kg.
So, weight of the Lead = $$\frac{{3}}{{24}}$$ = $$\frac{{1}}{{8}}$$ kg.
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LoginI know the formula for calculating a:b:c:d when a:b , b:c and c:d is given.
GIVEN IN QUEST
Z : C : T = 2 : 3 : 1 =6
C : T : L = 5 : 4 : 3=12
why cannt v take 6kg IF U WANT TO TAKE, THEN TAKE IT AS C : T : L = 5/2 : 4/2 : 3/2
BECAUSE Z:C:T AND C:T:L SHOULD BE EQUAL .
If equal weights of both alloys are melted together to form a third alloy,
C : T : L = 5 : 4 : 3
Z : C : T : L = 4 : 11 : 6 : 3
Weight of L = 3/24 = 1/8 (Ans.)