A and B are two alloys of gold and copper prepared by mixing metals in the ratio 5 : 3 and 5 : 11 respectively. Equal quantities of these alloys are melted to form a third alloys C. The ratio of gold and copper in the alloy C is -
A. 25 : 13
B. 33 : 15
C. 15 : 17
D. 17 : 15
Answer: Option C
Solution(By Examveda Team)
According to the question,\[\left. \begin{gathered} {\text{Alloy}}\,{\text{A}} \to 5{ \times _2}:3{ \times _2} = 8{ \times _2} \hfill \\ {\text{Alloy}}\,{\text{B}} \to 5\,\,\,\,\,\,\,\,:11\,\,\,\,\, = 16 \hfill \\ \end{gathered} \right]\] Equal quantity are mixed
$$\eqalign{ & {\text{Alloy A }} \to 10\,\,\,:\,\,\,6\,\,\,\, = 16 \cr & {\text{Alloy B }} \to {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \,5\,\,\,\,\,:\,\,\,11\, = 16 \cr & {\text{Alloy C }} \to {\bf{15}}\,\,\,:\,\,{\bf{17}} \cr} $$
Related Questions on Alligation
A. $$\frac{{1}}{{2}}$$ kg
B. $$\frac{{1}}{{8}}$$ kg
C. $$\frac{{3}}{{14}}$$ kg
D. $$\frac{{7}}{{9}}$$ kg
A. 81 litres
B. 71 litres
C. 56 litres
D. 50 litres
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